Two years ago , a father was five times as old as his son . Two years later , his age will be 8 more than three times the age of the son. If the present age of father be x and son be y then which of these pair of equation is correct.
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Given : Two years ago , a father was five times as old as his son . Two years later , his age will be 8 more than three times the age of the son.
To find : Father & Son present age
Solution:
present age of father = x
present age of son = y
Two years ago father age = x - 2
Two years ago son age = y - 2
Two years ago father was five times as old as his son
=> x - 2 = 5(y - 2)
=> x = 5y - 8
Two years later father age = x + 2
Two year later son age = y + 2
Two years later father age will be 8 more than three times the age of the son
=> x + 2 = 3(y + 2) + 8
=> x = 3y + 12
Equating x
5y - 8 = 3y + 12
=> 2y = 20
=> y = 10
x = 3y + 12 = 3(10) + 12 = 42
( 42 , 10) represent present Father age and son age
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