two years ago a father was five times as old as his son two years later his age will be 8 more than 3times the age of the son. find present ages
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Hey.
Here is your answer.
let the present age of son be x
so, 2 yrs ago
son x-2
father 5(x-2)= 5x -10
2 yrs later ,
son x+2
father 3(x+2)+8=3x+6+8=3x+14
also, father's age = 5x-10 +2+2=5x-6
so, 3x+14=5x-6
or, 5x-3x=14+6
or, 2x=20
so, x =10
so, age of son is 10yrs and father is 5×10-10+2=42 yrs
Thanks.
Here is your answer.
let the present age of son be x
so, 2 yrs ago
son x-2
father 5(x-2)= 5x -10
2 yrs later ,
son x+2
father 3(x+2)+8=3x+6+8=3x+14
also, father's age = 5x-10 +2+2=5x-6
so, 3x+14=5x-6
or, 5x-3x=14+6
or, 2x=20
so, x =10
so, age of son is 10yrs and father is 5×10-10+2=42 yrs
Thanks.
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