Math, asked by ajitsingh6075, 4 months ago

Two years ago , a father was five times as old as his son . Two years hence , the age of father will be 8 times more than three times the age of the son . So what are the present ages of father and the son?​

Answers

Answered by larshikhakrishnan
1

Answer:

Let father age be x, his son age be y.

Before 2 years,

⇒(x−2)=5(y−2)−−−−−−−(1)

After 2 years  

⇒(x+2)=8+3(y+2)−−−−−−−−(2)

From (1) x−5y+8=0

From (2)  

⇒x+2−3y−6−8=0

⇒x−3y−12=0

Solving them  

⇒−2y+20=0

⇒y=10

When y=10,x=42

So the present age of the father is 42 and the son age is 10.

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