Question

two years ago a father was five times as old as his son.two years later his age will be 8 more than three times the age of the son. find the present age of the son

Answer 1

Let son's present age be x

father's present age be y

2 years ago ;

son's age = x - 2

father's age = y - 2

but a/q ;

y - 2 = 5 ( x - 2 ) = 5x - 10

or, 5x - y = 8 _______________(i)

Two years later ;

son's age = x + 2

father's age = y + 2

but a/q ;

y + 2 = 8 + 3 ( x + 2 )

or, y + 2 = 8 + 3x + 6 = 3x + 14

or, 3x - y = -12 ________________(ii)

Subtracting eqn (ii) from eqn (i) ; we get

2x = 20

or, x = 20 / 2 = 10 (son's age)

y = 3x + 12 = 3×10 + 12 = 42 (father's age)