Question

Two years ago a father was four times as old as his son and after 5 year he will be 3 times old his son what is son age now son

Answer 1

Let Son's age 2 years ago be x years

So, Father's age 2 years ago be 4x years

After 5 years of present ages »

Son's age = (x + 7) years

Father's age = (4x + 7) years

According to Question,

(4x + 7) = 3(x + 7)

⇒ 4x + 7 = 3x + 21

⇒ 4x - 3x = 21 - 7

⇒ x = 14

Required ages 2 years ago »

Son's age = x = 14 years

Father's age = 4x = 4(14) = 56 years

Required present ages »

Son's age = (14 + 2) = 16 years

Father's age = (56 + 2) = 58 years

Hence, the present ages of Father and Son are 58 years and 16 years.

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