Two years ago , a father was three times as old as his son and two years hence twice his age will be equal to five times his son . Find their present age.
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2(f+2)=2(3s−4+2)=5(s+2)2(f+2)=2(3s−4+2)=5(s+2)
6s−4=5s+10=>s=146s−4=5s+10=>s=14
f=3s−4=3∗14−4=38
6s−4=5s+10=>s=146s−4=5s+10=>s=14
f=3s−4=3∗14−4=38
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princepriyanshu:
i was writing to some one else
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hope this will help you
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