Math, asked by taippaipai, 1 year ago

Two years ago , a father was three times as old as his son and two years hence twice his age will be equal to five times his son . Find their present age.

Answers

Answered by princepriyanshu
7
2(f+2)=2(3s−4+2)=5(s+2)2(f+2)=2(3s−4+2)=5(s+2)

6s−4=5s+10=>s=146s−4=5s+10=>s=14

f=3s−4=3∗14−4=38


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Answered by prerana123
4
hope this will help you
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