Question

TWo YEARS ago a father ws five times as old as his son. Two years later his age will be 8 more than three times the age of the son . Find the present age of father and son

Answer 1

33 is the answer..............................

Answer 2

Let's assume the age of the father is F and his son is S.

Now two years ago
(F-2) = 5(S-2)
F= 5S-8........(i)

Two year later from now
(F+2) = 3(S+2) + 8
F = 3S + 12........(ii)

equating equation (i) and (ii) we get
5S-8=3S + 12
S= 10 years.

substituting the value of S in equation (i) we get
F=42 years.