Question

two years ago,a man's age was three times the square of his son's age.In three years time,his age will be four times his son's age. find their present ages

please solve this question...

Answer 1

Let the present age of man=x
Present age of his son=y
Two years ago man age =x-2
Son age =y-2
According to question
x-2=3(y-2)^2
x-2=3(y^2+4-4y)
x-2=3y^2+12-12y
x+12y-3y^2=14
After three years
x+3=4(y+3)
x+3=4y+12
x-4y=9
After solving these equation we get x=29
Y=5