Question

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages.
ANSWER : 29years and 5 years
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I only could make out son's age(=5yrs)..see the pic
Can u plzz tell me... How to calc. the man's age?.... Tell if my understanding was wrong.. ​

Answer 1

ok so basically Let the man's current age be x and that of his son be y..

(x−2)=3(y−2) ^2......1

(x+3)=4(y+3)

x+3=4y+12

x=4y+9 .........2

put the value of x from equation 2 to 1

x=4y+9

4y+9−2=3(y ^2 +4−4y)

3y ^2 −16y+5=0

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3y ^2 −15y−y+5=0. (middle split method)

(3y−1)(y−5)=0 (by taking common)

so, y=1/3 which is not possible. it is coming from solving 3y-1 ..

it is not possible as age can't be in fraction.

so y =5

father's age =4(5)+9=29 years. (from equation 1)

Answer 2

Answer:

sir can you please please help me in Hindi??

अरिक्त शुद्ध है या आरिक्त???

it will be nice if u help me