Question

Two years ago, a man's age was three times the square of his son's age . In three years' time, his age will be four times his son's age. Find their present ages.

solve by quadratic equations


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Answer 1

Answer:

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages. And, the present age of son = x = 5 years.