Math, asked by sharanrao38, 1 year ago

two years ago a man was 5 times as old as his son. two years later his age will be 8 more than three times the age of his son,find the present age of the man and the son​

Answers

Answered by seema3269
0

let man age be x and son then two years ago x-2=5(y-2). two years later x+2=8+3(y+2). by solving these equation you will get answer

Answered by ANKIT0302
0

Step-by-step explanation:

hope this will help u.if any quarries ask me in comment box

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