Two years ago a man was 5 times as old as his son. Two years later he will be 8 more than 3 times the age of his son. Find the ages of the man and his son
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Step-by-step explanation:
two years ago:
Son = x
Man = 5x
two years later:
Son = x + 2
Man = 8 + 3x
5x+2=8+3x
5x-3x=8-2
2x=6
x=3
Therefore, the son = 3yrs
the man = 8+3(3) = 8+9 = 17
hope it helps
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