Question

Two years ago a man was 6 times as old as his son. After 18 years, he will be twice as old as his son. Their present ages (in years) are:

Answer 1

Step-by-step explanation:

let the age of father's present age be x

the age of son's present age be y

case 1)

x-2=6(y-2)

x-2=6y-12

x-6y=-10. (1)

case 2)

x+18=2(y+18)

x+18=2y+36

x-2y=18. (2)

solve eqs.(1) &(2) you will get:

-4y=-28

y=7years

from eq. (2)

x=32years