Question

Two years ago, a man was five times as old as his son. Two years later,
his age will be 8 more than three times the age of his son. Find the present ages.
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Answer 1

Answer:

let man age be x yrs

let son age be y yrs

According to the question

2 yrs ago

x-2 = 5(y-2)

$x - 5y + 8 = 0 \\ 2 \: years \: after \\ x + 2 = 3(y + 2) - 8 \\ x - 3y + 4 = 0$

Solving this by any method will give you the answer. Mark this as the brainiest