Two years ago a man was five times as old as his son. Two years later his age will be 8 more than
Answers
Given:-
- Two years ago, a man was five times as old as his son.
- Two years later, his age will be 8 more than three times the age of the son.
To find out:-
Find the present ages of the man and his son.
Solution:-
Let the present age of his son be a.
Then, the present age of the father = b
According to the question,
★ Two years ago,
⇒( b - 2 ) = 5 ( a - 2 )
⇒ b - 2 = 5a - 10
⇒ b = 5a - 8 .......( 1 )
★ Two years later,
b + 2 = 8 + 3 ( a + 2 )
⇒ b + 2 = 8 + 3a + 6
⇒ b + 2 = 3a + 14
⇒ b = 3a + 12.......( 2 )
From ( 1 ) and ( 2 )
5a - 8 = 3a + 12
⇒ 5a - 3a = 12 + 8
⇒ 2a = 20
⇒ a = 10
Now,
Substituting the value of a in equation ( 1 )
b = 5a - 8
b = 5 × 10 - 8
b = 50 - 8
b = 42
Hence,the present age of man and his son are 42 and 10 respectively.
Two years ago a man was five times as old as his son. Two years later his age will be 8 more than..
_______________
✒Given : -
- Two years ago a man was five times as old as his son ...
- After two years his age will be 8 more than 3 times of his son's age ...
✒To Find : -
- Present age of man and his son = ?
✒Let ,
- Let present age of Son be = x
- Let presebt age of man be = y
★ Two years ago ★
➮ (1)
★ After two years ★
➮ (2)
✒Now ,
✒By Equation : -
✒Now ,
✒On Substituting Values of x in Eq. (1) : -
Therefore , Present age of man is 42 years and Present age of his son is 10 years ..