Question

Two years ago, a woman's age was three times the square of her son's age. Three years later, her age will be four times her son's age. What will be the sum of their ages 5 years hence?

Answer 1

Answer:

Let son's age 2 years ago be y

Then woman's age 2 years ago=3*y^2

Three years later==>

Son's age=y+3

Woman's age=4(y+3) OR 4(3*y^2)

(Equate 4(y+3)=4(3*y^2) to get both their ages)

after getting both ages add 5 to each. Then add both the values obtained.

Step-by-step explanation: