Two years ago, ashok was 3 times as old as his son and two years hence, twice his age will be equal to 5 times that of his son.find their present age.
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Step-by-step explanation:
Let the present age as Son =x yrs
Present age of father =y yrs
Two years ago :
Son's age =(x−2) yrs
Father's age =(y−2) yrs
Therefore, y−2=3(x−2)
3x−y=4 ...(1)
After Two years:
Son's age =(x+2) yrs
Father's age =(y+2) yrs
Therefore, 2(y+2)=5(x+2)
5x−2y=−6 ....(2)
Solving equations 1 & 2, we get
x=14 & y=38
Hence, present age of Son is 14 yrs and present age of father is 38 yrs.
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