Math, asked by avibikki, 6 hours ago

Two years ago, ashok was 3 times as old as his son and two years hence, twice his age will be equal to 5 times that of his son.find their present age.

Answers

Answered by tishyameshram2526
1

Answer:

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Step-by-step explanation:

Let the present age as Son =x yrs

Present age of father =y yrs

Two years ago :

Son's age =(x−2) yrs

Father's age =(y−2) yrs

Therefore, y−2=3(x−2)

3x−y=4 ...(1)

After Two years:

Son's age =(x+2) yrs

Father's age =(y+2) yrs

Therefore, 2(y+2)=5(x+2)

5x−2y=−6 ....(2)

Solving equations 1 & 2, we get

x=14 & y=38

Hence, present age of Son is 14 yrs and present age of father is 38 yrs.

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