Question

Two years ago Dileep was 3 times as old as his son and Two years hence twice his age will be equal to 5 times that of his son. Find their present ages.​

Answer 1

Answer:

it is 8 is the correct answer for this question

Step-by-step explanation:

because we have to add then subtract the question

Answer 2

Given :

• Two years ago Dileep was 3 times as old as his son.
• Two years hence twice his age will be equal to 5 times that of his son.

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To find :

• The present age of Dileep and his son.

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Concept :

In this question we are provided with the relation between the Dileep and his son's . Assuming the age of Dileep's son to be any variable we will get the age of Dileep . Then after following the second criteria given to us i.e., ‎ after two years , twice his age will be equal to 5 times that of his son , we would frame up an appropriate equation . Solving the equation we will get our final answers .

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Solution :

⠀⠀⠀⠀⠀Let the present age of Dileep's son be x.

‎» Two years ago son's age = ( x-2 )

» Two years ago Dileep's age = 3 ( x-2 )

» Present age of Dileep

⠀⠀⠀⠀3 ( x-2 ) + 2 = 3x - 6 + 2 = ( 3x-4 )

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» ‎Two years hence ,

Age of Dileep = ( 3x-4 ) + 2 = 3x - 4 + 2 = 3x - 2

Age of his son = x + 2

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» Framing equation ,

‎ Twice Dileep's age will be equal to 5 times that of his son.

$\sf\multimap\:5(x+2)=2(3x-2)$

$\sf\multimap\:5x+10=6x-4$

$\sf\multimap\:5x-6x=-4-10$

$\sf\multimap\:\cancel{-}x=\cancel{-}14$

$\small{\underline{\boxed{\mathrm{\multimap\:x=14}}}}$

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» Before calculating their present age let's verify if we got correct value of x or not.

Verifying :

$\sf\to\:5(x+2)=2(3x-2)$

$\sf\to\:5(14+2)=2(3 \times 14 -2)$

$\sf\to\:5(16)=2(42-2)$

$\sf\to\:80=2(40)$

$\sf\to\:80=80$

Hence Verified!~

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» Now calculating their present age by substituting x as 14,

⠀⠀⠀⠀Son's present age = x = $\small\red{\tt\pmb{14~yrs}}$

⠀⠀⠀⠀Dileep's present age :

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 3x-4

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 3 × 14 - 4

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 42 - 4

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = $\small\red{\tt\pmb{38~yrs}}$

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