Math, asked by vishu1757, 1 year ago

two years ago dilip was three times as old as his son 2 years hence twice his age will be equal to five times that of his son the dilips present age is

Answers

Answered by ALTAF11
7
Hey Friend !!

[ above is ur ans with solution ]

Present age of Dilip = 38 years
and that of His son = 14 years !!
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Answered by AnIntrovert
10

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!

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