Question

. Two years ago. Dilip was three times as old as his son and two years hence, twice his age will
be equal to five times that of his son. Find their present ages.​

Answer 1

Answer:

Let the present age of Dilip be x

..................................his son be y

A/q

x - 2 = 3y .............(1)

x - 3y = 2 ...............(2)

again

2( x+2) = 5y

2x + 4 = 5y ...........(3)

2x - 5y = -4.............(4)

eq. (2)×2

2x - 3y = 4............(5)

Now , eq. (4) - (5)

2x -. 5y. = -4

2x. - 3y. =. 4

-. +. -

---------------------------------–---

0. - 2y = -8

y = -8/-2

= 4

Now, from eq. (1)

x - 2 = 3y

x = 3×4 +2

= 14

Hence,

Present age of Dilip = x = 14 yrs

..................his son = y = 4 yrs...

Ans...