Math, asked by amishafilomeena1003, 9 months ago

Two years ago, Dilip was three times as old as his son and two years
hence, twice his age will be equal to five times that of his son. Find
their present ages.

please answer this question if you know the answer with showing all the workings please answer fast

Answers

Answered by SivaSaiSahasraani

Step-by-step explanation:

Let the age 2 yrs ago

Son =x

Dilip =3x

Present age

Son= x+2

Dilip =3x+2

Age after 2 yrs

Son =x+2+2 =x+4

Dilip =3x+2+2=3x+4

According to question

5(x+4)=2(3x+4)

5x+20=6x+8

5x-6x=8-20

-x=-12

Negative negative cancel

x=12

Present age of son =12+2=14

Present age of Dilip =3 *12+2=36+2=38

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Answered by XxMissPaglixX

${\huge{\mathtt{\red{AnSwEr:-}}}}$

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2 years ago,

Son's age = x

Dilip's age = 3x

Present age of Son = x+2

Present age of Dilip = 3x+2

After 2 years,

Son's age = x+2+2 = x+4

Dilip's age = 3x+2+2 = 3x+4

A/Q 2(3x+4) = 5(x+4)

6x+8 = 5x+20

x = 12

∴ ᴘʀᴇsᴇɴᴛ ᴀɢᴇ ᴏғ sᴏɴ = x+2 = 12+2 = 14

ᴘʀᴇsᴇɴᴛ ᴀɢᴇ ᴏғ ᴅɪʟɪᴘ = 3x+2 = 3x12+2 = 38

${\huge{\mathtt{\red{Thank\:You}}}}$

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