Question

two years ago, dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. find their present age

Answer 1

Dilip age was three times as old as his son
D = 3S
two years hence, twice his age will be equal to five times that of his son.
2(D + 2) = 5(S + 2)
Replace D on left hand side with 3S
2(3S + 2) = 5(S + 2)

6S + 4 = 5S + 10
6S - 5S = 10 - 4
S = 6.
Dilip is aged 20 years old
Son is 8 years old

Hope This Helps :)

Answer 2

let the age of son be x yrs. two years ago,the age of Dilip (x-2)yrs.
two years ago, age of Dilip 3(x-2)yrs.=3x-6yrs.
the present age of Dilip =3x-6+2=3x-4yrs.
atq
=2[3x-4+2] =5[x+2]
=2[3x-2] = 5x+10
=6x-4 = 5x+10
=6x-5x = 10+4
=x = 14
therefore, the present age of
Dilip= 3x-4 = 3×14-4 =42-4=39yrs.
son= x= 14 yrs.