Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Then the present age of Dilip is..................
Answers
Let the present age of dilip and his son be X and Y year's.
Before two years age of dilip = (X-2) years
Before two years age of his son = (Y-2) years
According to question,
(X-2) = 3(Y-2)
X-2 = 3Y -6
X-3Y -2+6 = 0
X -3Y = -4.....(1)
Again,
After two years age of dilip = (X+2) years
After two years age of his son = (Y+2) years
According to question,
2(X+2) = 5(Y+2)
2X +4 = 5Y +10
2X -5Y = 10-4
2X -5Y = 6......(2)
From equation (1) we get,
X-3Y = -4
X = -4+3Y....(3)
Putting the value of X in equation (2)
2X -5Y = 6
2 × (-4+3Y) -5Y = 6
-8+6Y -5Y = 6
-8+Y = 6
Y = 6+8
Y = 14 years.
Putting the value of Y in equation (3)
X = -4+3Y
X = -4 + 3 × 14
X = -4 + 42
X = 38 years
Age of dilip = X = 38 years
And ,
The age of his son = Y = 14 years.
Hence,
The present of age of dilip and his son is 38 and 14 years respectively.
HOPE IT WILL HELP YOU..... :-)
Answer:
Hi friend,
Let the present age of dilip and his son be X and Y year's.
Before two years age of dilip = (X-2) years
Before two years age of his son = (Y-2) years
According to question,
(X-2) = 3(Y-2)
X-2 = 3Y -6
X-3Y -2+6 = 0
X -3Y = -4.....(1)
Again,
After two years age of dilip = (X+2) years
After two years age of his son = (Y+2) years
According to question,
2(X+2) = 5(Y+2)
2X +4 = 5Y +10
2X -5Y = 10-4
2X -5Y = 6......(2)
From equation (1) we get,
X-3Y = -4
X = -4+3Y....(3)
Putting the value of X in equation (2)
2X -5Y = 6
2 × (-4+3Y) -5Y = 6
-8+6Y -5Y = 6
-8+Y = 6
Y = 6+8
Y = 14 years.
Putting the value of Y in equation (3)
X = -4+3Y
X = -4 + 3 × 14
X = -4 + 42
X = 38 years
Age of dilip = X = 38 years
And ,
The age of his son = Y = 14 years.
Hence,
The present of age of dilip and his son is 38 and 14 years respectively.
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