Question

Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Then the present age of Dilip is..................

Answer 1

Let present age of Dilip be x and his son be y.
So, age of Dilip two years ago =x-2
age of son two years ago =y-2
A/Q
x-2 = 3*(y-2)
x =3*(y-2) + 2 - - - - - - - (1)
After 2 years,
age of Dilip =x+2
age of son =y+2
A/Q
2(x+2) = 5(y+2)
x+2 = 5(y+2)/2 - - - - - - - -(2)
Putting value of x in eq. (2)
[3*(y-2)+2]+2 = 5(y+2)/2

Now solve the equation to get the value of y and put value of y in eq. (1)to get value of x.

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Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

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