Question

Two years ago, Dilip was three times as old as his son and two years
hence, twice his age will be equal to five times that of his son. Find
their present ages.(Linear Equation in One Variable)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Son age =x

Dilip age =3x

Present age of son= x + 2

Present age of Dilip = 3x + 2

AFTER 2 YEARS

Son age =x + 2 + 2= x + 4

Dilip age = 3x + 2 + 2= 3x + 4.

BY QUESTION ..

2(3x + 4)=5(x +4)

6x + 8=5x + 20

x = 12

hence,

Present age Of son =x + 2 = 12 +2 = 14 age .

Present age of Dilip = 3x + 2 = 3× 12 + 2 = 38 age.

HOPE IT HELP YOU..