Question

Two years ago dilip was three times as old as hus son and twice his age will be equal ti five times that of his son find there present age

Answer 1

Answer:

Dilips age=40

Sons age=8

Step-by-step explanation:

Let age of dilip= x

Let age of son=y

Now,

Two years ago,

Age of dilip = x-2

Age of son =y-2

Given:  dilip was three times as old as hus son

==>x-2 = 3(y-2)

==>x-2=3y-6

==>x-3y=-4------------1.

Given: twice his age will be equal ti five times that of his son

==>2x=5y

==>x=5y/2-------------2.

Applying 2 in 1

==>5y/2-3y= -4

==>5y-6y=-8

==>-y=-8

==>y=8

x=5y/2

=5*8/2

=5*4

=40