two years ago dilip was three times as old is his son and two years hence twice his age will be equal to five times that of his son ,find their present ages?
Answers
Answered by
101
A N S W E R :
❍ Let's say, that the present age of Dilip and his son be x and y years respectively.
But, Two years ago —
- Dilip's age = (x – 2) years
- Son's age = (y – 2) years
- Two years ago Dilip was three times as old as his son.
➟ Dilip's age = 3(Son's age)
➟ (x – 2) = 3(y – 2)
➟ x – 2 = 3y – 6
➟ x = 3y – 4 ⠀⠀⠀⠀⠀⠀—eq.( I )
⠀⠀⠀⠀
- And, two years hence twice his age (dilip's age) will be equal to five times that of his son.
Therefore,
⠀⠀⠀
⠀⠀⠀⠀⠀⠀
⠀⠀⠀
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀
⠀
Hence, their ages are —
- Present age of Dilip, x = 38 years
- Present age of Dilip's son, y = 14 years
⠀⠀⠀⠀
Answered by
53
Given :-
Two years ago dilip was three times as old is his son and two years hence twice his age
To Find :-
Present ages
Solution :-
Let the son age be x
Age of father = 3x
Two years ago
Age of son = x - 2
Age of father = 3(x - 2)
Now
After 2 years
Age of son = x + 2
Age of father = 3(x - 2) + 2 = 3x - 6 + 2 = 3x - 4
ATQ
Age of son = 14 years
Age of father = 3(14) - 4 = 42 - 4 = 38 years
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