Two years ago, father was three times as old as his son and two years hence, twice
his age will be equal to five times that of his son. Find their present ages
Answers
Answered by
9
Answer:
present age of father 38 yrs
Attachments:
Answered by
2
let the present age of father is x
so , the father age become 3x
According to question
2 years before
son age = x - 2
so , father age become 3x - 2
a . t. q.
2 (3x- 2 ) = 5 ( x - 2 )
6x - 4 = 5x - 10
6x - 5x = -4 + 10
x = 6
so , the age of son is x = 6
and age of father is 3x = 3 × 6 = 18
hope it helps please mark it as brainliast
Similar questions