Question

Two years ago, father was three times as old as his son and two years hence, twice
his age will be equal to five times that of his son. Find their present ages​

Answer 1

Answer:

present age of father 38 yrs

Answer 2

let the present age of father is x

so , the father age become 3x

According to question

2 years before

son age = x - 2

so , father age become 3x - 2

a . t. q.

2 (3x- 2 ) = 5 ( x - 2 )

6x - 4 = 5x - 10

6x - 5x = -4 + 10

x = 6

so , the age of son is x = 6

and age of father is 3x = 3 × 6 = 18

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