Math, asked by punamburnwal1234, 9 months ago


Two years ago, father was three times as old as his son and two years hence, twice
his age will be equal to five times that of his son. Find their present ages​

Answers

Answered by saraswathisreekanth
9

Answer:

present age of father 38 yrs

Attachments:
Answered by priyanshi3821
2

let the present age of father is x

so , the father age become 3x

According to question

2 years before

son age = x - 2

so , father age become 3x - 2

a . t. q.

2 (3x- 2 ) = 5 ( x - 2 )

6x - 4 = 5x - 10

6x - 5x = -4 + 10

x = 6

so , the age of son is x = 6

and age of father is 3x = 3 × 6 = 18

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