Question

two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. find their present ages.​

Answer 1

Step-by-step explanation:

Let the age of the son be x(two years ago)

Two years ago

Father = 3x

Son =x

Now

2*(3x+2)=(x+2)*5

6x+4=5x+10

6x-5x=10-4

x=6

Therefore present age of son=6+2

=8

Therefore present age of father=(6*3)+2

=20

This guy became father at the age of 12!!!!