Two Years Ago Father Was Three Times As Old As His Son And Two Years Hence Twice His Age Will Be Equal To Five Times That Of His Son Find Their Presents Ages
Answers
Answered by
1
Answer:
Let us consider
Son's age = X
0.3KB/S *
Two years ago son's age X- 2
His Father's age at that time = 3(x - 2)
Present age of Father 3X - 6+ 2
The present age of Father = 3X - 4
Two years hence father's age = 3X - 4 + 2
Two years hence father's age 3X- 2
Two years hence son's age X + 2
Given:
5 x (X + 2) = 2 x (3x - 2)
5X + 10 = 6X -
X = 14
Step-by-step explanation:
Answered by
0
Answer:
5 x (X + 2) = 2 x (3x - 2)
5X + 10 = 6X -
X = 14....
... . .
......
ok
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