Math, asked by Anonymous, 1 year ago

Two years ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present ages

Answers

Answered by Anonymous
1
let the father age be x and son be y
then given
x-2=3(y-2)-----1
and also given
2(x+2)=5(y+2)------2



solving 1 and 2
x-3y= -4----3
2x-5y=6----4
multiplying eq 3 by 2
y=14 and x=38
hope this helps you....

Anonymous: Not understood
Anonymous: The answer is correct but I don't know how you did it
Anonymous: If age of son x
Anonymous: Then age of father 2x
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