two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find there present age
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let the present age of father be x and that of son be y
Acc. to question
Case 1
(x-2) = 3 (y-2)
x-2 = 3y-6 ....... (1)
Case 2
2 (x+2) = 5 (y+2)
2x+4 = 5y+10 ...... (2)
solve the two equations
Acc. to question
Case 1
(x-2) = 3 (y-2)
x-2 = 3y-6 ....... (1)
Case 2
2 (x+2) = 5 (y+2)
2x+4 = 5y+10 ...... (2)
solve the two equations
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