Math, asked by Ravigah2829, 1 year ago

Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their present ages.


ANS: father's age ,38
Son's age ,14

Answers

Answered by mrakashverma2003
0

Let present age of father is x and his daughter age be y

A T Q

Two years ago father would be x-2

Daughter would be y-2



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