Question

two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son find their present ages.

Answer 1

let present age of father be X and present age of son be y.
x-2 =3(y-2)
2(x+2)= 5(y +2)
solving the equations, we get,
X=38
y= 14