Two years ago father was three times as old as his son and two years hence twice his age will be equal to five times of that his son find their present ages
Answers
Answered by
2
Hello Bud❤❤
here's ua answer :
Let father's age be x and sons age be y
2 years ago :
X-2=3 (y-2)
3y-x=4
2 years hence:
2 (x+2)=5 (y+2)
2x+4=5y+10
2x-5y=6
Now we equate the equations
2 (3y-x=4)
-5y+2x=6
6y-2x=8
-5y+2x=6
now subtract the above 2 equatio
y=14
Put the value of y in any of the equation where x comes out to be 38
So:
y is 14
x is 38
HOPE IT HELPS UH
BYE SEE UH AGAIN!!!!
here's ua answer :
Let father's age be x and sons age be y
2 years ago :
X-2=3 (y-2)
3y-x=4
2 years hence:
2 (x+2)=5 (y+2)
2x+4=5y+10
2x-5y=6
Now we equate the equations
2 (3y-x=4)
-5y+2x=6
6y-2x=8
-5y+2x=6
now subtract the above 2 equatio
y=14
Put the value of y in any of the equation where x comes out to be 38
So:
y is 14
x is 38
HOPE IT HELPS UH
BYE SEE UH AGAIN!!!!
Answered by
0
Answer:
Step-by-step explanation:
2+3x-5
Similar questions