Question

Two years ago father was three times as old as his son two years hence twice his age will be equal to five times that of his son find their ages?​

Answer 1

Answer:

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Let us consider

Son’s age = X

Two years ago son’s age = X – 2

His Father’s age at that time = 3(X – 2)

Present age of Father = 3X – 6 + 2

The present age of Father = 3X – 4

Two years hence father’s age = 3X – 4 + 2

Two years hence father’s age = 3X – 2

Two years hence son’s age = X + 2

Given:

5 × (X + 2) = 2 × (3X – 2)

5X + 10 = 6X – 4

X = 14

Son’s present age X = 14 years.

Father’s present age = (3 × 14) – 4

Father’s present age = 38 years.

Answer 2

Answer:

38 years

Explanation:

5 x ( X + 2) = 2 × ( 3X _ 2)

5 X + 10 = 6× _ 4

×= 14

Son's present age is ×=14

Father's present age =( 3 × 14 ) _ 4

Father's present age is = 38 year