Math, asked by reetatiwari23, 1 year ago

Two years ago fatherwas three times as old as son and two years hence twice his age will be equal to five time his son .find there present ages




yuvraj19023: hi i am yuvraj

Answers

Answered by khadijakhan13
2
Hey mate here is your ANSWER

Let son's age =x

Two years ago son's age=x-2

His father age at that time=3(x-2)

present age of father=3x-6+2
=3x-4

Two years hence father's age=3x-4+2
=3x-2

Two years hence son's age=x+2

Given:-5*(x+2)=2*(3x-2)

5x+10=6x-4

10+4=6x-5x

14=x

Son's present age=14 years
Father's present age=38 years .



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khadijakhan13: reetatiwari23 plz mark me as a brainiest.
yuvraj19023: yuvraj
yuvraj19023: god of u
Answered by sajal95
2
this is the required answer you asked
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