Two years ago fatherwas three times as old as son and two years hence twice his age will be equal to five time his son .find there present ages
yuvraj19023:
hi i am yuvraj
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Hey mate here is your ANSWER
Let son's age =x
Two years ago son's age=x-2
His father age at that time=3(x-2)
present age of father=3x-6+2
=3x-4
Two years hence father's age=3x-4+2
=3x-2
Two years hence son's age=x+2
Given:-5*(x+2)=2*(3x-2)
5x+10=6x-4
10+4=6x-5x
14=x
Son's present age=14 years
Father's present age=38 years .
HOPE THIS ANSWER WILL HELPFUL FOR YOU
Mark me as a brainiest please.
Let son's age =x
Two years ago son's age=x-2
His father age at that time=3(x-2)
present age of father=3x-6+2
=3x-4
Two years hence father's age=3x-4+2
=3x-2
Two years hence son's age=x+2
Given:-5*(x+2)=2*(3x-2)
5x+10=6x-4
10+4=6x-5x
14=x
Son's present age=14 years
Father's present age=38 years .
HOPE THIS ANSWER WILL HELPFUL FOR YOU
Mark me as a brainiest please.
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this is the required answer you asked
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