Question

two years ago, Mohit was three times as old as his son and two years hence ,twice of Mohit age will be equal to 5 times that of his son . and then the present age of Mohit is _____


( A ) 14 years

( B ) 38 years

( C ) 32 years

( D ) 34 years

Answer 1

Let the age of Mohit's sons = x
2 years ago Mohit son's age = (x-2)
Mohit age at that time = 3(x-2)
Present age of Mohit = 3(x-2)+2
3x-6+2 = 3x-4
2 years hence Mohit's age = (3x-4)+2
2 years hence his son's age (x+2)
Acc. to question,
5(x+2) = 2(3x-2)
5x+10 = 6x-4
10+4 = 6x-5x
14 = x
present age of Mohit's son = 14 years
present age of Mohit = 3x-4 = 3×14-4 = 42-4 =
38 years


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Answer 2

Answer:

THE ANSWER IS 38 YEARS

Step-by-step explanation:

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