Question

Two years ago, Mohit was three times as old as his son and two years hence, twice of his age will be equal to five times that of his son.Then the present age of Mohit is :

Answer 1

Let the age of son be x years.

Then Two years ago,

Son's age = x -2

Mohit's age = 3(x-2)

Two years hence,

Son's age = x+2

Mohit's age = 3(x-2 ) + 4 ( 2 years will bring him to present and another two, to two years hence)

A/Q

2 × 3(x-2)+4 = 5(x+2)

2(3x-6+4) =5x+10

6x-12+8=5x+10

6x-4=5x+10

6x-5x=10+4

x=14

So, son's age =14 years

Mohit's age = 3(x-2) +2 ( +2 is for bringing him to present from two years back age)

=3(14-2)+2

=3×12+2

=36+2

=38 years

$\bf{Hope\:it\:helps}$