two years ago, montu was three times as old as his daughter and two years hence, twice his age will be equal to five times that of his daughter. find their present ages.
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Step-by-step explanation:
let his son age be x
two years ago sons age =x-2
his fathers age at that time =3(x-2)
present age of father =3x-6+2=3x-4-----(1)
two years hence fathers age =3x-4+2=3x-2
two years have sons age =x+2
GIVEN:
5(x+2)=2(3x-2)
5x+10=6x-4
10+4=6x-5x
x=14
substitute in equation (1)
fathers age will be 3x-4
so 3×14-4=38
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