Question

two years ago my age was four times my son's age eight years ago my age was 10 times my son's age what is my son's age now ​

Answer 1

Answer:

father age be x and son age be y

Step-by-step explanation:

two years ago my age four times of my son = x+4=y

Eight year ago my age was ten times of son= x+10=y

${x}^{2} + 14 = y \\x \times x + 14 = y \ \\ : 2x + 14 = y \: \: \\x = \frac{14}{2} y \: \: \: \\ x = 7y$