Question

Two years ago, Raju was thrice as old as his daughter and six
years later, he will be four years older than twice her age.
How old are they now?

plezzzzzzzzzzzzzzzzzz send a fast answer with explane

and answer is (14&38)

pizzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz explane

Answer 1

Answer:

answer is in the attachment.....

Answer 2

Given :-

Age of Raju 2 years ago = Present age - 2

Age of daughter 2 years ago = Present age - 2

Age of Raju 6 years after = Present age + 6

Age of daughter 6 years after = Present age + 6

To Find :-

Present age of Raju.

Present age of his daughter.

Solution :-

Let us consider,

Present age of Raju = x

Present age of daughter = y

Two years back,

Age of Raju = x - 2

Age of daughter = y - 2

According to the question,

$\sf x-2=3(y-2)$

$\sf x-3y=-4 \qquad ...(1)$

Six years later,

Age of Raju = x + 6

Age of daughter = y + 6

As per the given info,

$\sf x+6=2(y+6)+4$

$\sf x-2y=10 \qquad ...(2)$

Subtracting equation (2) from (1),

$\sf -y=-14$

$\sf y=14$

Therefore, the present age of daughter is 14 years.

Substituting the value of y in equation (1),

$\sf x-3 \times 14=-4$

$\sf x=38$

Therefore, the present age of Raju is 38 years.