Question

two years ago ramesh was three times as old as his sons two years latter twice of his age will be equal to the five times that of his sons age find their present ages

Answer 1

let ramesh age be x and his sons age will be y
two years ago their age will be,
x-2=3( y-2)
x-2=3y-6
x-3y=-6+2
x-3y= -4 (equation 1)
two years latter their age will be,
2(x+2)=5(y+2)
2x+4=5y+10
2x-5y=10-4=6(equation 2)
multiply 2 in equation 1
we get,
2x-6y=-8 ( by elimination method)
2x-5y= 6
(-) (+) (-)
----------------
0-y = -14
y= 14
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x-3y=-4
x-3(14)=-4
x-48=-4
x=-4+48
x=44
therefor age of father is 48 and his son's age is 14
Hope this helps you!!!