Two years ago rohan was 3 times old as his son and two years hence twice his age will be equal to five times that of his son.find their present age
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Let Rohans age be x and sons age be y.
x - 2 = 3(y - 2)
x - 2 = 3y - 6
x - 3y = -4 – equation 1
2(x + 2) = 5(y + 2)
2x + 4 = 5y + 10
2x - 5y = 6 – equation 2
equation 1 × 2, 2x -6y = -8 –equation 3
equation 3 - 2 , -y = -14
y = 14
Put y=14 in equation 1
x - 42 = -4
x = 38.
Rohan is 38 and his son is 14.
x - 2 = 3(y - 2)
x - 2 = 3y - 6
x - 3y = -4 – equation 1
2(x + 2) = 5(y + 2)
2x + 4 = 5y + 10
2x - 5y = 6 – equation 2
equation 1 × 2, 2x -6y = -8 –equation 3
equation 3 - 2 , -y = -14
y = 14
Put y=14 in equation 1
x - 42 = -4
x = 38.
Rohan is 38 and his son is 14.
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