Math, asked by mahammadali, 1 year ago

two years ago sahil was three times as old as his son and two years hence twice his age will be equal to five times that of his son .find their present ages

Answers

Answered by rockdahiya123
5

Answer:

Let age of sahil be y

Age of sahil's be x

Step-by-step explanation:

A. T. Q

3(x-2) =(y-2)

3x-6=y-2

3x-y=4 ( mark equation 1)

2 year hence

5(x+2) = 2(y+2)

5x+10= 2y+6

5x-2y=-4 ( mark equation 2)

Multiply equation 1 by 2 we get

6x-2y=8( mark equation 3)

Sutract equation 3 from 2 we get

x=14

Put x in equation 1 we get

y=38

Age of sahil=38

Age of his son=14

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