Two years ago Salim was thrice as old as his daughter and six years later he will be twice her age how old they are now?
Answers
Let the present age of salim be x and yhat of his daughter be y
2 years ago age of salim=x-2
age of daughter=y-2
(x-2)=3(y-2)
x-3y=-4
after 6 years
x+6=4+2(y+6)
x-2y=10
Upon solving the above two eq we get y=14
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Answer:-
Let the age of Salim be S years and his daughter's be D years.
Given:
Two years ago Salim was thrice as old as his daughter.
Age of Salim before two years = S - 2
Age of Salim's daughter before two years = D - 2.
According to the above condition,
→ S - 2 = 3(D - 2)
→ S = 3D - 6 + 2
→ S = 3D - 4 -- equation (1).
And,
After six years he will be twice her age.
→ S + 6 = 2(D + 6)
→ S + 6 = 2D + 12
Substitute S value from equation (1).
→ 3D - 4 = 2D + 12
→ 3D - 2D = 12 + 4
→ D = 16
Substitute D value in equation (1)
→ S = 3(16) - 4
→ S = 44
Hence, Age of Salim = 44 years and his daughter's age = 16 years.