Question

Two years ago salim was thrice as old as his daughter and six years later he will be four years older than twice her age .How old are they now​

Answer 1

Salim is now 7 years old.

Answer 2

Answer:

Let the presnt ages of ----

Salim = x and Daughter = y

3 years ago age of

salim = x-3 and daughter = y-3

therefore

A.T.Q

# x-3 = 3 (y-3)

# x-3 = 3y - 9

#x - 3y + 6 = 0 -------- (i

and 6 years later ages of

salim = x + 6

and

daughter = y + 6

therefore

A.T.Q

#x + 6 = 2 (y+6) + 4

#x + 6 = 2y + 12 + 4

#x - 2y - 10 = 0 --------- (ii)

therefore from (i) and (ii)

on appling cross multiplication method

x = (-3) (-10) - (-2) (6) / (1) (-2)

-(1) (-3)

x = 30 + 12 / (-2) + 3

x = 42/1 = 42 ans.

now

y = (6) (1) - (-10) (1) / (1) (-2)

-(1) (-3)

y = 6 + 10 / (-2) + 3

y = 16/1 = 16 ans.

therefore

x = 42 and y = 16

therefore present age of

slaim = 42

daughter = 16