Question

Two years ago, salim was thrice as old as his daughter and six years later, he will be four years older than twice her age.how old are they now

Answer 1

Let Salim's and his daughter's age 2 years ago be 3x and x respectively.
=> 2(x+6)+4 = 3x+6
=> 2x+12+4 = 3x+6
=> 2x+16 = 3x+6
=> 16-6 = 3x-2x
=> 10 = x
=> Daughter's age 2 years ago = 10
=> Salim's age 2 years ago = 3x = 3*10 = 30
THEREFORE:
=> Daughter's present age = 10+2 = 12
=> Salim's present age = 30+2 = 32

Answer 2

Answer:

14 years, 38 years

Step-by-step explanation:

Let the age of daughter two years be x years.

Two years ago:

Age of Salim = 3x

6 years later:

Age of daughter = x + 2 + 6 = x + 8

Age of Salim = 3x + 2 + 6 = 3x + 8.

Given that 6 years later he will be 4 years older than twice her age.

⇒ 3x + 8 = 2(x + 8) + 4

⇒ 3x + 8 = 2x + 16 + 4

⇒ 3x + 8 = 2x + 20

⇒ x = 12

Therefore:

Present age of daughter = x + 2 = 14

Present age of Salim = 3x + 2 = 38

Hope it helps!