Question

two years ago salon was thrice as old his daughter and six years later he will be four years older than twice her age . How old are they now

Answer 1

Let the present age of salim be x and yhat of his daughter be y2 years ago age of salim=x-2age of daughter=y-2(x-2)=3(y-2)x-3y=-4 after 6 yearsx+6=4+2(y+6)x-2y=10Upon solving the above two eq we get y=14 x=38

Answer 2

Answer:

14 years, 38 years

Step-by-step explanation:

Let the age of daughter two years be x years.

Two years ago:

Age of Salim = 3x

6 years later:

Age of daughter = x + 2 + 6 = x + 8

Age of Salim = 3x + 2 + 6 = 3x + 8.

Given that 6 years later he will be 4 years older than twice her age.

⇒ 3x + 8 = 2(x + 8) + 4

⇒ 3x + 8 = 2x + 16 + 4

⇒ 3x + 8 = 2x + 20

⇒ x = 12

Therefore:

Present age of daughter = x + 2 = 14

Present age of Salim = 3x + 2 = 38

Hope it helps!