Question

Two years ago Swati was three times the age of her daughter 10year hence she would be twice the age of her daughter.what is Swati ‘s age now.

Answer 1

Answer:

28 years

Step-by-step explanation:

Given:

Swati was 3 times her daughter's age 2 years ago

swathi will be 2 times her daughter's age 10 years later

To Find: Swati's presnt age

let her present age be 'x' and her daughter's 'y'

x - 2 = 3(y - 2)

x -2 = 3y - 6

x - 3y = -6 +2

x - 3y = -4

x = -4 +3y.........(1)

10 years later

x+10 = 2(y+10)

x + 10 = 2y + 20

x - 2y = 20-10

x - 2y = 10

From (1)

- 4 + 3y - 2y = 10

-4 + y = 10

y = 10 + 4

y = 14

Her daughter's age = 14

from (1)

x = -4 + 3y

x = - 4 + 3(14)

x = 42 - 4

x = 28

∴ Swathi 's present age is 28 years

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